Question

Please solve it fast...​

Answer 1

Explanation:

Hope this will help you

Answer 2

Answer:

$\bigstar$ Given:

⇒ A wire of Resistance (R) = 9 Ω that is cut into three equal length.

⇒ These three lengths are connected in parallel with each other.

$\bigstar$ To Find:

⇒ New Resistance $R\,'$

$\implies\dfrac{ \;\;R\; '} {R}$

$\bigstar$ Solution:

→ When the wire is cut into three equal parts, then new resistance $R\,'$

$\green{\boxed{R\,' = \dfrac{9}{3} = 3 \;\Omega}}$

$\mathrm{Therefore,}$

$\blue{\boxed{R\,'=R_1 = R_2 = R_3 = 3\,\Omega}}$

→ Parallel Equivalent Resistance

$\dfrac{1}{R_p} = \dfrac{1}{R_1} \;+\;\dfrac{1}{R_2} \;+\;\dfrac{1}{R_3}$

After Substitution,

$\dfrac{1}{R_p} = \dfrac{1}{3} \;+\;\dfrac{1}{3} \;+\;\dfrac{1}{3}$

$\dfrac{1}{R_p} = \dfrac{3}{3}$

$\red{\boxed{R_p = 1\,\Omega}}$

∴ Equivalent resistance of the combination is 3 ohm.

$\sf{To \;Calculate }\;\; \dfrac{R\,'}{R}$

$\aqua{\boxed{\implies\dfrac{ \;\;R\; '} {R}= \dfrac{3}{9} = \dfrac{1}{3}}}$