Math, asked by scholarrr, 4 months ago

please solve it fast​

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Answers

Answered by Anonymous
1

Step-by-step explanation:

cosec^4©-cot^4©=cosec^2©+cot^2©

use

a^4-b^4= (a^2)^2-(b^2)^2

(a^2+b^2)(a^2-b^2)

so

(cosec^2©+cot^2©)(cosec^2©-cot^2©)=(cosec^2©+Cot^2©)

cosec^2©-cot^2©=1

mark as brilliant

40

Answered by charshaly
1

Answer:

LHS = cosec4  theta - cosec2 theta

       = cosec2 theta (cosec2 theta-1)

       = cosec2 theta * cot2 theta

       = (1+cot2 theta) cot2 theta

       = cot2 theta + cot4 theta

∴ LHS = RHS

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