Math, asked by vaibhavi200542, 2 months ago

please solve it fast!

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Answered by abhirupsarmah04

1

secA/cotA+tanA

=>1/cosA ÷ 1/cotA+tanA

=> cosA × cotA+tanA

=> cosA × ( cosA/sinA+sinA/cosA )

=>cosA × ( cos^2A+sin^2A/sinAcosA )

=>cosA× 1/ sinA cosA

=> 1/sinA

and 1/sinA can be also written as cosecA

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