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cot^2(80)=[cot80]^2=[cot(90-10)]^2=tan^2(10),
sec^2(10)-tan^2(10)=1,
sin15cos75+cos15sin75 =sin(15+75)=sin90=1,
cos(theta)sin(90-theta)+cos(90-theta)sin(-theta)=sin90=1,
so the answer of the question is=1+1=2
sec^2(10)-tan^2(10)=1,
sin15cos75+cos15sin75 =sin(15+75)=sin90=1,
cos(theta)sin(90-theta)+cos(90-theta)sin(-theta)=sin90=1,
so the answer of the question is=1+1=2
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