Question

Please solve it fast ​

Answer 1

Step-by-step explanation:

We have,

$|x| < \frac{a}{x}$

$\implies \frac{ | x |^{2} - a}{ |x| } < 0$

$\implies |x|\in(\infty, -\sqrt{a}) U (0,\sqrt{a})$

Answer 2

Answer:

<

x

a

\begin{gathered} \implies \frac{ | x |^{2} - a}{ |x| } < 0 \\ \end{gathered}

⟹

∣x∣

∣x∣

2

−a

<0

\implies |x|\in(\infty, -\sqrt{a}) U (0,\sqrt{a})⟹∣x∣∈(∞,−

a

)U(0,

a

)