Physics, asked by payalvermasuman, 1 month ago

please solve it fast​

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Answered by itzPapaKaHelicopter
3

\huge \fbox \blue{Answer:}

 \textbf{Given Distance}  \: (d) = 2cm

 \textbf{Mass}  \: (m) = 1.67 \times  {10}^{ - 27} kg

 \textbf{Magnitude }  \: (E) = 3.34 \times  {10}^{3}  {NC}^{ - 1}

 \textbf{Acceleration}  \: (a) =  \frac{ F}{m}

 =  \frac{eE}{m}

 =  \frac{1.6 \times  {10}^{ - 19}  \times 3.34 \times  {10}^{3} }{1.67 \times  {10}^{ - 27} }

 = 3.2 \times  {10}^{11}  {ms}^{ - 2}

⇒s = 0 +  \frac{1}{2}  {at}^{2}

∴t =  \sqrt{ \frac{2s}{a} }

 =  \sqrt{ \frac{2 \times 0.02}{3.2 \times  {10}^{11} } }

 = 3.54 \times  {10}^{ - 7} s

 \\  \\  \\  \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}

Answered by rishabh994
2

Answer:

Plz.. refer to the 3 attachments...

Hope you understand it

Thank you

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