please solve it fast
Answers
Answer:
98000
Step-by-step explanation:
LET LEFT OVER MONEY BE X
MONEY SPENT FOR RENT=1/10
MONEY SPENT FOR REPAIRING HIS CAR=2/5(or) 4/10.
TOTAL MONEY SPENT=1/10+4/10=5/10.
=5x/10=49000
HIS SALARY=49000*2=98000.
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Step-by-step explanation:
Given :-
Arun spent 1/10 of his salary to pay to the rent of his house and 2/5 of his salary on the repair of his car and another Rs. 15000 salary for his school fees of his children.He also spent
Rs. 21000 on some another items and he was left with Rs. 13000.
To find :-
Find his salary ?
Solution :-
Let Arun's salary be Rs. X
Money spent on his house rent = 1/10 of his salary
=> (1/10) of X
=> (1/10)×X
=> (1×X)/10
=> X/10
Money spent on his house rent = Rs. X/10
Money spent on the repair of his car
= 2/5 of his salary
= (2/5)×X
=> (2×X)/5
=> 2X/5
Money spent on the repair of his car = Rs. 2X/5
Money spent on his children's school fees
= Rs.15000
Money spent on some other items = Rs. 21000
Total Arun's expenditure
= (X/10)+(2X/5)+15000+21000
=> (X/10)+(2X/5)+36000
LCM of 10 and 5 = 10
=> (X+4X+360000)/10
=> (5X+360000)/10
His savings = Salary - Expenditure
=> X-[(5X+360000)/10]
=> [10X-(5X+360000)]/10
=> (10X-5X-360000)/10
=> (5X-360000)/10
According to the given problem
Money he was left = Rs. 13000
=> His saving money = Rs. 13000
=> (5X-360000)/10 = 13000
=> 5X-360000 = 13000×10
=> 5X-360000 = 130000
=> 5X = 130000+360000
=> 5X = 490000
=> X = 490000/5
=> X = 98000
Therefore, Arun's salary = Rs. 98000
Answer:-
The salary of Arun is Rs. 98000
Check :-
The salary of Arun is Rs. 98000
Money spent on his house rent = 1/10 of his salary
=> 98000/10
=> Rs. 9800
Money spent on the repair of his car
= 2/5 of his salary
=2×98000/5
=> 2×19600
=> Rs. 39200
Money spent on his children's school fees
= Rs.15000
Money spent on some other items = Rs. 21000
Total Arun's expenditure
=> 9800+39200+15000+21000
=> Rs. 85000
His savings = Salary - Expenditure
=> 98000-85000
=> 13000
His savings = He was left with Rs. 13000
Verified the given relations in the given problem.