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in triangle abc
angle a+ angle b+angle c=180
40+ angle b+90=180
angle b+130=180
angle b=180-130=50
in triangle ebd
angle b+ angle bed+ angle x=180
120+50+x=180
170+x=180
x=180-170=10
angle a+ angle b+angle c=180
40+ angle b+90=180
angle b+130=180
angle b=180-130=50
in triangle ebd
angle b+ angle bed+ angle x=180
120+50+x=180
170+x=180
x=180-170=10
Answered by
3
Hi DEAR
GIVEN÷
A=40
BED=120
C=90
WE NEED TO FIND ANGLE B FIRST
SO WE KNOW THAT SUM OF ALL THE ANGLES IN TRIANGLE IS =180
SO,IN TRIANGLE ABC
<a+<b+<C=180("< "represent angle)
REPLACE THE. VALUE OF ANGLE
==>40+<b+90=180
==><b+130=180
==><b=180-130
==><b=50
SO, ANGLE B IS
AGAIN IN TRIANGLE EBD
<e+<b+<x=180
REPLACE THE VALUE
==>120+50+X=180
==>X+170=180
==>X=180-170
==>X=10
SO The VALUE OF X IS
protestant:
r u SATISFIED
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