Math, asked by subham3226, 11 months ago

please solve it fast

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Answered by oyo
2
in triangle abc
angle a+ angle b+angle c=180
40+ angle b+90=180
angle b+130=180
angle b=180-130=50
in triangle ebd
angle b+ angle bed+ angle x=180
120+50+x=180
170+x=180
x=180-170=10
Answered by protestant
3
<b>HELLO !
Hi DEAR

GIVEN÷

A=40

BED=120

C=90

WE NEED TO FIND ANGLE B FIRST

SO WE KNOW THAT SUM OF ALL THE ANGLES IN TRIANGLE IS =180

SO,IN TRIANGLE ABC

<a+<b+<C=180("< "represent angle)

REPLACE THE. VALUE OF ANGLE

==>40+<b+90=180

==><b+130=180

==><b=180-130

==><b=50

SO, ANGLE B IS &lt;marquee&gt;50degree&lt;/marquee&gt;

AGAIN IN TRIANGLE EBD

<e+<b+<x=180

REPLACE THE VALUE

==>120+50+X=180

==>X+170=180

==>X=180-170

==>X=10

SO The VALUE OF X IS
&lt;marquee&gt;10&lt;/marquee&gt;

protestant: r u SATISFIED
protestant: hi subham
subham3226: ya
protestant: can u plz press the crown on my answer box if u SATISFIED my answer
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