Question

please solve it......fast

Answer 1

${t}^{2} - 5t + 3 = 0 \\ \alpha \beta = 3 \\ \alpha + \beta = 5 \\ { \alpha }^{4} { \beta }^{3} + { \alpha }^{3} { \beta }^{4} \\ = {( \alpha \beta )}^{3} ( \alpha + \beta ) \\ = (3) {}^{3} (5) \\ = 27 \times 5 = 135$
ANS: opt(3)

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