Question

PLEASE SOLVE IT FAST......​

Answer 1

Answer

Step-by-step explanation:

p(x)= x^2+px-4

p(-4)= (-4)^2+-4p-4=0

16-4p-4=0

p=3

p(x)=x^2+p(x)+q

Substitute the value of p,

x^2+3x+q=0

It is given has equal roots,

Therefore b^2-4ac=0

here, a=1 , b=3 and c=q

3×3-4×1×q=0

9-4q=0

q=9/4