Question

please solve it fast 85

Answer 1

sum of first 14 terms is 1050
so
$sn \: = \frac{n(2a \: + \: (n - 1)d)}{2}$
1050 = 14( 2(10) + (14-1)d)/2
2100 = 14( 20 + 13d)
150 = 20 + 13d
130 = 13d
d = 10
so
20th terms is
a + (20-1)d
10 + 19(10)
200 answer....