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If PO=28cm then, PR=2(28)=56cm
And we know that
length of diagonal of square=sqrt(2) times the length of its side [proved by Pythagoras theorem]
If x is the side of square then,
56=(x) sqrt(2)
X=56/sqrt2 =28(sqrt2)
So, each side of square would be of length=28(square root of 2)
And we know that
length of diagonal of square=sqrt(2) times the length of its side [proved by Pythagoras theorem]
If x is the side of square then,
56=(x) sqrt(2)
X=56/sqrt2 =28(sqrt2)
So, each side of square would be of length=28(square root of 2)
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