Question

Please solve it fast....​

Answer 1

SOLUTION

Factorise :-

1-64a³-12a+48a²

=(1)³-(4a)³-3(1)²(4a)+3(1)(4a)²

This is in the form of a³-b³-3a²b+3ab².

So,

a³-b³-3a²b+3ab² = (a-b)³

Here,a=1,b=4a

So,

(1)³-(4a)³-3(1)²(4a)+3(1)(4a)² = (1-4a)³

So, the required answer is (1-4a)³

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