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Answered by
4
Answer:
tan(A+B)/cot(A-B)=tan^2A-tan^2B/tan^Atan^B
LHS:
=tan(A+B)×tan(A-B)
=tanA+TanB/1-tanAtanB × tanA-tanB/1-tanAtanB
=tan^A-tan^B/1-tan^Atan^B
=RHS
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Answered by
20
AnswEr :
Given that,
LHS :
We Know That,
tan∅ = 1/cot∅
Thus,
Now,
Also,
Thus,
We know that,
(a + b)(a - b) = a² - b²
Hence, ProveD
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