Question

Please solve it fast for getting brainliest answer.....
Two wires of same material having length and radii in
the ratio 3 : 4 and 3: 2 respectively, are connected in
parallel with a battery of 6 V, the ratio of current is......​

Answer 1

Answer: Final Answer : 9:16

Explanation:

Steps:

1) We know that the Resistance of a same wire is proportional to (l/A) .

where L = Length of wire,

A = Area of cross section

And, Area is proportional to d^2 ,

where 'd' is diameter of wire.

=> Resistance is proportional to

2) We have,

Ratio of their length = 1:2

Ratio of diameters = 2:3

=> Ratio of Area of cross- section = 2^2:3^2 = 4:9

=> Ratio of resistance :

9:16

3) Since, current in series circuit is same.

=> Ratio of Potential difference across wires :

R(1) : R(2) = 9:16

Hence, Required Ratio is 9:16

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Answer 2

Answer:

We know that

R

1

=ρ

A

1

I

1

=ρ

πr

1

2

I

1

R

2

=ρ

πr

2

2

I

2

R

2

R

1

=

I

2

I

1

×(

r

1

r

2

)

2

V/I

2

V/I

1

=

I

2

I

1

⋅(

r

1

r

2

)

2

(∵ wire connected in parallel)

I

1

I

2

=

4

3

×(

3

2

)

2

I

1

:I

2

=9×4:4×3

=3:1