Question

please solve it faster and right there is my exam today.​

Answer 1

Answer:

u can see in the pic

Step-by-step explanation:

hope it'll help you

Answer 2

Required Answer:-

Given To Simplify:

• $\sf \dfrac{ {x}^{^{7}/_{2}} \times \sqrt{y} }{ {x}^{{}^{5}/_{2}} \times \sqrt{ {y}^{3} } }$

Solution:

Given that,

$\sf = \dfrac{ {x}^{^{7}/_{2}} \times \sqrt{y} }{ {x}^{{}^{5}/_{2}} \times \sqrt{ {y}^{3} } }$

$\sf = \dfrac{ {x}^{^{7}/_{2} -^{5}/_{2}} \times \sqrt{y} }{\sqrt{ {y}^{3} } } \: \: \: \blue{ \bigg( \dfrac{ {x}^{y} }{ {x}^{z} } = {x}^{y - z} \bigg)}$

$\sf = \dfrac{ {x}^{^{2}/_{2}} \times \sqrt{y} }{\sqrt{ {y}^{3} } }$

$\sf = \dfrac{ {x}^{1} \times \sqrt{y} }{\sqrt{ {y}^{3} } }$

$\sf = \dfrac{ {x}^{1} \times {y}^{^{1}/_{2}} }{({y}^{3})^{{}^{1}/_{2}}} \: \: \: \blue{ \bigg( \sqrt[n]{y} = {y}^{^{1}/_{n}}\bigg)}$

$\sf = \dfrac{ {x}^{1} \times {y}^{^{1}/_{2}} }{{y}^{^{3}/_{2}}} \: \: \: \blue{ \bigg( {( {x}^{y} )}^{z} = {x}^{yz} \bigg)}$

$\sf = {x}^{1} \times {y}^{^{1}/_{2} -{}^{3}/_{2}} \: \: \: \blue{ \bigg( \dfrac{ {x}^{y} }{ {x}^{z} } = {x}^{y - z} \bigg)}$

$\sf = {x}^{1} \times {y}^{^{ - 2}/_{2}}$

$\sf = {x}^{1} \times {y}^{ - 1}$

$\sf = \dfrac{x}{y}$

→ Therefore, the result after evaluating the expression is x/y.

Answer:

• x/y.

•••♪