Question

please solve it fastly

Answer 1

csc square theta - tan square (90-theta)=csc square theta - cot square theta=1=LHS
sin square theta - sin square (90-theta)=sin square theta +cos square theta=1=RHS (sin square(90- theta)=cos square theta)
There fore LHS=RHS

Answer 2

let '©' be theta
first of all , in LHS
convert cosec²© into 1/sin²©
then
convert tan²(90-©) into cot²©
now,
convert cot²© into cos²©/sin²©
here,
1/sin²© - cos²©/sin²© = 1 - cos²©/sin²©
which is equal to sin²©/sin²© = 1



Now, in RHS
convert sin²©(90-©) into cos²©
then in RHS,. sin²© + cos² © will be observed
hence sin²© + cos² © = 1


so,
LHS=RHS
1=1