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Answer:
0×25 root×11
Step-by-step explanation:
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Step-by-step explanation:
We are given,
a(4th) = 0
We know that,
a(nth) = a + (n - 1)d
Let the 1st term be a and common difference be d
So,
a(4th) = a + (4 - 1)d
0 = a + 3d
a + 3d = 0
a = -3d ----- 1
Now, similarly,
a(25th) = a + (25 - 1)d
a(25th) = a + 24d
From eq.1 we get,
a(25th) = (-3d) + 24d
a(25th) = 21d ----- 2
And,
a(11th) = a + (11 - 1)d
a(11th) = a + 10d
From eq.1 we get,
a(11th) = (-3d) + 10d
a(11th) = 7d ----- 3
Now, if we observe closely,
From eq.2 and eq.3
21d = 3 × 7d
∴ a(25th) = 3 × a(11th)
Hence proved
Hope it helped and believing you understood it........All the best
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