Question

please solve it guys​

Answer 1

✞︎ Given series are x - 7 , x - 2 , x + 3......10 terms

✯︎ here a = x - 7 ; d = 5 ; n = 10

➪︎ $Sn = \frac{n}{2} (2a + (n - 1)d)$

➪︎ $Sn = \frac{10}{2} (2(x - 7) + (10 - 1)5)$

➪︎ $Sn = 5 (2x - 14 + 45)$

➪︎ $Sn = 5(2x + 31)$

➪︎ $Sn = 10x + 155$

✰︎ Sum of 10 terms is 10x + 155....

Answer 2

$\large{ \bold{ \red{ \underline{ \underline{Question...}}}}}$

$\large{ \sf{find \: the \: sum \: of \: ap \: x - 7,x - 2,}} \\ \large{ \sf{x + 3....upto \: 10 \: terms}}$

$\bold{ \large{ \green{ \underline{ \underline{Answer...}}}}}$

$\large{ \sf{10x + 155}}$

$\large{ \bold{ \red{ \underline{ \underline{Solution...}}}}}$

$\large{ \sf{ \to \: u \: must \: know..}} \\ \\ \boxed{ \green{ \large{ \sf{ \red{s}n = \frac{n}{2} (2a + (n - 1)d)}}}} \\ \\ \large{ \sf{where \to \: \: \red{s}n = sum \: of \: n \: terms}} \\ \\ \large{ \sf{ \to \: n = no. \: of \: terms}} \\ \\ \large{ \sf{ \to \: a = first \: term}} \\ \\ \large{ \sf{ \to \: d = common \: difference}}$

$\large{ \sf{ \to \: \red{given} \: a =( x - 7)}} \\ \\ \large{ \sf{ \: d = 5 \: and \: n = 10}} \\ \\ \large{ \sf{ by \: using \: formula }}....\\ \\ { \large{ \sf{ \to \red{s}n = \frac{n}{2}(2a + (n - 1)d}}} \\ \\ \large{ \sf{ \to \: \red{s}10 = \frac{10}{2} (2(x - 7) + (10 - 1)5)}} \\ \\ \large{ \sf{ \to \red{s}10 = 5(2x - 14 + (9)5)}} \\ \\ \large{ \sf{ \to \red{s}10 = 5(2x - 14 + 45)}} \\ \\ \large{ \sf{ \to \red{s}10 = 5(2x + 31)}} \\ \\ \large{ \sf{ \boxed{ \to \red{s}10 = 10x + 155}}}$

$\large{ \bold{ \pink{required \: answer = 10x + 155}}}$