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this is English section on brainly. kindly post it in maths section.
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216x^3-1/27
Cube root of 216 is 6 and 27’s cube root is 3 so
(6x)^3-(1/3)^3
So by using a^3-b^3= (a-b)(a^2+b^2+ab)
(6x-1/3)(6x^2+1/3^2+6x*1/3)
(17/3)(36x^2+1/9+6/3x^2)
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Cube root of 216 is 6 and 27’s cube root is 3 so
(6x)^3-(1/3)^3
So by using a^3-b^3= (a-b)(a^2+b^2+ab)
(6x-1/3)(6x^2+1/3^2+6x*1/3)
(17/3)(36x^2+1/9+6/3x^2)
This is your answer
If you are satisfied with my answer pls press the thank icon. It will really help me
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