please solve it how can we find its area
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here area of triangle HDC
= 1/2 b×h
= height CH and base is DH
1/2 × 2 × 4
= 4 cm sq. area of triangle HDC
area of trapezium BFCH
= 1/2(+ of ll line) × height
remaining I will solve later sorry I have no time
= 1/2 b×h
= height CH and base is DH
1/2 × 2 × 4
= 4 cm sq. area of triangle HDC
area of trapezium BFCH
= 1/2(+ of ll line) × height
remaining I will solve later sorry I have no time
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