Please solve it I have exam
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Answer:
x = 1
Step-by-step explanation:
⇒
⇒
⇒ (2bx + 4ax + 2ab)(2a + b + x) = 4abx
⇒ 4abx + 8a²x + 4a²b + 2b²x + 4abx + 4ax² + 2bx² + 4ax² + 2abx = 4abx
⇒ 8ax(a+x) + 4a²b + 2bx(b+x) + 6abx = 0
⇒ [8a + 2b]x² + [8a² + 6ab + 2b²]x + 4a²b = 0
⇒ x = {-(8a² + 6ab + 2b²) ± √(8a² + 6ab + 2b²)² - 16a²b(8a+2b)} / {2(8a+2b)}
⇒ x = 1
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