Question

please solve it I need it please​

Answer 1

teta=45°

i) sin2teta=2sinteta costeta

sin2×45=2 sin 45× cos 45

sin90°=2 ×1/root2 × 1/ root2

1=2×1/2

1=2/2

1=1

•°• sin2 teta = 2sin teta cos teta.

ii)cos 2 teta=cos²teta - sin²teta

cos 2×45= cos45² - sin45²

cos 90°= (1/root 2)² - (1/root2)²

0 =1/2 - 1/2

0 = 0

•°• cos2 teta = cos²teta - sin²teta

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