Question

Please!
solve. it
i shall be thankful to you.
(Solve it in rough copy with its fig.) ​

Answer 1

HELLO MATE!

Let AB be the height of the tower

BY DATA: CD=10m

NOW,

tan60°=AB/AC

√3= AB/AC

AC=AB/√3----- 1

ALSO,

tan30°=AB/AD

1/√3=AB/AC+CD

1/√3=AB/AB/√3+10----------FROM 1

1/√3=AB/AB+10√3/√3

AB+10√3/√3=AB√3

AB+10√3=3AB

10√3=3AB-AB

10√3=2AB

AB=10√3/2

AB=5√3m

.•. Height of the tower is 5√3m

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