Question

please Solve it I want Solution... ​

Answer 1

Answer:

$( {( {2 \sqrt{2} )}^{x} )}^{x + 1} = {( \sqrt{8}) }^{12} \\ { (\sqrt{8}) }^{ {x}^{2} + x } = {( \sqrt{8} )}^{12} \\ {x}^{2} + x = 12 \\ {x}^{2} + x - 12 = 0 \\ {x}^{2} + (4x - 3x) - 12 = 0 \\ {x}^{2} + 4x - 3x - 12 \\ x(x + 4) - 3(x + 4) \\ (x - 3)(x + 4) \\ x = 3 \\ x = - 4$

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Answer 2

Answer:

x=-4 , x=3

Step-by-step explanation:

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