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this might be ur answer
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Marvels123:
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D is mid pt. of line AC
DC= AD
so, Angle ADB= 90°,angle ABD=45°
In ∆BDC, BD= DC
angle DBC= 45°
then, ABC= angle ( ABD + DBC) = 90° hence proved
DC= AD
so, Angle ADB= 90°,angle ABD=45°
In ∆BDC, BD= DC
angle DBC= 45°
then, ABC= angle ( ABD + DBC) = 90° hence proved
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