Question

please solve it
If you I will mark as brain list​

Answer 1

Let M, P and C denote the students studying Mathematics, Physics and

Chemistry

And U represents total students

So, n(U)= 200,

n(M) = 120, n(P) = 90

n(C) = 70, n(Mn P) = 40, n(Pn C) = 30 n(Mn C) = 50, n(M UP UC)' = 20

...n(M UP UC) = n(U) - n(MUP UC)

→ 20 = 200 − n(M UP U C)

= n(M UP U C) = 180

→ n(M UP UC) = n(M) + n(P) + n(C)

-n(Mn P) - n(P n C) - n(C nM) + n(C n

Mn P)

.. 180 = 120 +90 + 70 - 40 - 30 - 50 + n(C n

→ 180 = 280 - 120 + n (C n Mn P)

→ n(P n C n M) = 300 - 280 = 20

Hence, the number of students studying all three subjects is 20.