Question

Please SOLVE it immediately

Answer 1

Answer:

4. (I) 130°+x=180° (Linear pair)

x=180°-130°

x=50°

(ii) 60°+50°+y=180° (angle sum property)

110°+y=180°

y=180°-110°

y=70°

angle 1= 60°

angle 2= 50°

angle 3= 70°

5. (a) 42° = angle 1 (vertically opposite angles)

42°+45°+z=180° (angle sum property)

87°+z=180°

z=180°-87°

z=93°

100°+42°+angle 2=180° (angle sum property)

142°+angle 2=180°

angle 2=180°-142°

angle 2=38°

38°+x=180° (linear pair)

x=180°-38°

x=142°

93°+y=180°

y=180°-93°

y=87°

b) (it's not clear, so i am sorry i wasn't able to do that, I hope you understand)

c) 120°-angle 1=180° (linear pair)

angle 1=180°-120°

angle 1=60°

60°+a+90°=180° (angle sum property)

150°+a=180°

a=180°+150°

a=30°

20°+90°+angle 2=180° (angle sum property)

110°+angle 2=180°

angle 2=180°-110°

angle 2=70°

30°+70°+b=180°

100°+b=180°

b=180°-100°

b=80°

d) 30°+55°+c=180°

85°+c=180°

c=180°-85°

c=95°

c=angle 1 (vertically opposite angles)

30°=angle 2 (vertically opposite angles)

55°= angle 3 (vertically opposite angles)

(rest is not clear, I hope you understand)

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