Math, asked by kherapratibha2, 2 months ago

please solve it is very urgent
I will mark you brainliest if you will answer correctly ​

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Answers

Answered by syedmateensma
1

Answer:

(9³ x a⁷ x 15² x 80 x b⁵)/(3⁴ x a⁵ x 5³ x b²)

= (9³ x a^7-5 x 15² x 80 x b^5-2)/(3⁴ x 5³)

= {(3²)³ x a² x (5 x 3)² x 80 x b³}/(3⁴ x 5³)

= (3^6-4 x a² x 5² x 3² x 80 x b³)/5³

= 3^2+2 x a² x 5^2-3 x 80 x b³

= 3⁴ x a² x 5^-1 x 80 x b³

= (3⁴ x a² x 80 x b³)/5

= (3⁴ x a² x (8 x 2 x 5))/5

= (3⁴ x a² x 8 x 2 x 5)/5

= 3⁴ x a² x 16

= 81 x a² x 16

= 1296a²

pls mark me as the brainliest and thank me

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