Question

please solve it it is important in full explanation​

Answer 1

Answer:

Step-by-step explanation:

(x +20) + 55 + (3x-5)= 180     {Angle Sum property}

x+2+55+3x-5 = 180

4x+52=180

4x=180-52

4x=128

x=128/4

x=32

AOC=x+20

       =32+20

       =52

BOD=3x-5

       =3*32 - 5

       =96-5

       =91

Answer 2

The answer is angles $\angle AOC=47.5\°$  and  $\angle DOB=77.5\°$.

Step-by-step explanation:

We are given a straight line AOB having three angles in it,

$\angle AOC = (x+20)$

$\angle COD =55\°$

$\angle DOB = (3x-5)$

and we have to find angles $\angle AOC$  and $\angle DOB$  by calculating 'x'.

• Formula used,

A straight line have total angle is 180°.

• Calculation for 'x'

we have

$\angle AOC = (x+20)$

$\angle COD =55\°$

$\angle DOB = (3x-5)$

by using formula we can write,

$\angle AOC+\angle COD + \angle DOB=180\°$

$(x+20)+55+(3x-5)=180\°$

$x+20+55+3x-5=180\°$

$4x+70\°=180\°$

$4x=180\°-70\°$

$4x=110\°$

$x=\frac{110}{4}$

$x=27.5$

we get the value of x as $x=27.5$.

• Calculating  $\angle AOC$  and $\angle DOB$

$\angle AOC = (x+20)$

           $=27.5+20$

          $=47.5\°$

$\angle DOB=3x-5$

            $=3*27.5-5$

            $=82.5-5$

           $=77.5$

We get the answer of this question as $\angle AOC=47.5\°$  and  $\angle DOB=77.5\°$.