Question

Please solve it
It's really urgent
Me and friends are preparing for our tenth examinations

Answer 1

aloha!


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◆see if the wire gets divided into two parts then the circuit is said to be parallel.
◆but if the wire is just folded it would be in series.

now,

you see current from a to b gets divided into two this means they are in parallel.

and also, R1 and R2 are in series because the wire isn't divided into two here at F .
similarly, R3 and R4 are in series.

all of them are of 10 ohm

now Req1,2. of R1 and R2 = 10 + 10
= 20 ohm------------(1)
similarly,Req3,4 R3 + R4 = 10 + 10
= 20 ohm------------(2)

now, as we combine the two which are in series we get this diagram (2)

here R1 and R2 are in parallel so,

1/Req = 1/20 + 1/20

1/Req = 2/20

1/Req = 1/10

Req = 10 ohm


now, we have to find the current.

V= IR
3= I × 10
I = 3/10
I= 0.3 A

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hope it helps ☺️