Question

Please solve it...it's very important and don't do any fraud please​

Answer 1

$x + \frac{1}{x} = 4 \\ {(x + \frac{1}{x} )}^{2} = {4}^{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = 16 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 16 - 2 \\ {( {x}^{2} + \frac{1}{ {x}^{2} } )}^{2} = {14}^{2} \\ {x}^{4} + \frac{1}{ {x}^{4} } + 2 = 196 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 194$

Answer 2

Answer :

$x + \frac{1}{x} = 4 \\ \\ \ \bf on \: squaring \: both \: sides : \\ \\ (x + \frac{1}{x} ) {}^{2} = (4) {}^{2} \\ \\ x {}^{2} + \frac{1}{x {}^{2} } + 2 = 16 \\ \\ x {}^{2} + \frac{1}{x {}^{2} } = 16 - 2 \\ \\ x {}^{2} + \frac{1}{x {}^{2} } = 14 \\ \\ \bf on \: squaring \: both \: sides : \\ \\(x {}^{2} + \frac{1}{x {}^{2} } ) {}^{2} = (14) {}^{2} \\ \\ x {}^{4} + \frac{1}{x {}^{4} } + 2 = 196 \\ \\ x{}^{4} + \frac{1}{x {}^{4}} = 196 - 2 \\ \\ \boxed{ \bf x{}^{4} + \frac{1}{x {}^{4}} = 194}$

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