Please solve it its easy
a vector A=sqrt3 - 1j is rotated clockwise direction through an angle 60 degree to obtain another vector B.what is the value of A.B.plz solve it i need help
sivaprasath:
what do you mean by sqrt3 ?
root of 3
root 3 i^ - 1 j^ = A ?
no its 3^(1/2)
ya
A = root 3 i cap - 1j cap ?
yes
ok
(Done), Mark my ans. as brainliest,. Hope you understand,. something atleast,.
Answers
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Answer:
A . B = 2 units
Explanation:
Given :
A vector A=√3 i - 1j is rotated clockwise direction through an angle 60 degree to obtain another vector B.what is the value of A . B
Solution :
A=√3 i - 1j
We know that dot product of any two vectors = Product of magnitudes of two vectors × cos θ (where θ = angle between them)
⇒ A . B = |A| |B| cosθ
Since, |B| = |A| ( same vector at different angle)
⇒ |A| = units.
⇒ |B| = |A| = 2 units,.
__
⇒ A . B = |A| |B| cos 60° = 2 × 2 × = 2
⇒ A . B = 2
Thx, The question is ,. Did you understand something
??
yes ,i was unsure about the measure of vector B.i was so stupid that i didnt realised that the magnitude of vectors will remain the same only the components will change
Sometimes , it happens,.
Even I did a mistake in class 11 annual exam,. I wrote 1 + 1 = 1
not that,
I wrote (3)^2 + 1 = 4 , and lost 5 marks
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