Math, asked by anishka56, 10 months ago

please solve it its urgent.

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Answered by BrainlyConqueror0901
17

\blue{\bold{\underline{\underline{Answer:}}}}

 \green{ \therefore   \text{8,13,21,34,55,89,144,233,377,610}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline{ \bold{Given : }}} \\  \implies series  = a,b,(a + b),(a + 2b) \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: (2a + 3b).(3a + 5b),(5a + 8b) \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: (8a + 13b),(13a + 21b),(21a + 34b) \\  \\  \bold{Where : } \\   \circ \:  a = 8 \\   \circ \: b = 13 \\  \\  \red{\underline{ \bold{ To \: Find: }}} \\  \implies 10 \: fibonacci \: numbers =  ?

• According to given question :

 \text{ Putting \:  values \: of \: a \: and  \: b}\\   \implies First \: number = a = 8 \\  \\  \implies Second \: number = b = 13\\  \\  \implies 8 + 13 = 21 \\  \\  \implies 13 + 21 = 34\\   \\  \implies 21 + 34 = 55\\  \\  \implies 34 + 55 = 89 \\  \\ \implies 55 + 89 = 144  \\  \\  \implies 89 + 144 = 233 \\  \\  \implies 144 + 233 = 377 \\   \\ \implies 233 + 377 = 610  \\ \\  \therefore  \text{numbers \: are} \\   \green{\implies   \text{8,13,21,34,55,89,144,233,377,610}} \\   \\  \blue{\text{fibonacci \: numbers : }} \\  \implies  \text{A \: series \: of \: numbers \: in \: which } \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \text{sum \: of \: two \: preceding \: numbers \:} \\  \:  \:  \:  \:  \:  \:  \:  \:  \:   \text{is \: equal \: to \: next \: number }

For verifcation :

 \bold{Verfication : } \\  \implies Sum \: of \:all \: numbers = 11 \times 7th \: number \\  \\  \implies 8 + 13 + 21 + 34 + 55 + 89 +  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 144 + 233 + 377 + 610 = 11 \times 1584 =  (5a + 8b) \\  \\  \implies  1584= 11 \times (40 + 104) \\  \\  \implies 1584 = 11 \times 144 \\  \\  \implies 1584 =  1584  \\     \:  \:  \:  \:  \:  \:  \: \green{\huge\text{Verified}}

Answered by jatindevrajput
0

{ \bold{given : }}} \\ \implies series = a.b.(a + b).(a + 2b) \\ \: \: \: \: \: \: \: \: \: \: \: (2a + 3b).(3a + 5b).(5a + 8b) \\ \: \: \: \: \: \: \: \: \: \: (8a + 13b).(13a + 21b).(21a + 34b) \\ \\ \bold{where : } \\ \circ \: a = 8 \\ \circ \: b = 13 \\ \\ \red{\underline{ \bold{ to \: find: }}} \\ \implies 10 \: fibonacci \: numbers = ?[/tex]

• According to given question :

[tex] \text{ putting \: values \: of \: a \: and \: b}\\ \implies first \: number = a = 8 \\ \\ \implies second \: number = b = 13\\ \\ \implies 8 + 13 = 21 \\ \\ \implies 13 + 21 = 34\\ \\ \implies 21 + 34 = 55\\ \\ \implies 34 + 55 = 89 \\ \\ \implies 55 + 89 = 144 \\ \\ \implies 89 + 144 = 233 \\ \\ \implies 144 + 233 = 377 \\ \\ \implies 233 + 377 = 610

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