Question

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Answer 1

Answer:

Cofficient of Static Friction = 0.66

Explanation:

See the Attachment For explanation.

Thanks for asking.

Answer 2

$\huge\underline\mathfrak\red{Answer}$

AS THE BLOCK JUST START MOVING SO IN SUCH CASE YOU NEED TO CONSIDER ZERO ACCELERATION OF BOTH BODY....

NEWTON'S SECOND LAW OF MOTION

THE NET FORCE ACTING ON THE BODY IS DIRECTLY PROPORTIONAL TO THE ACCELERATION OF THE BODY BUT IN THIS CASE ACCELERATION IS ZERO SO THERE IS NO NET FORCE. SO WE JUST NEED TO EQUATE FORCES ON BOTH MASSES.

Frictinal force=¶Mg

where ¶ is the coefficient of friction

M is the mass of body that is horizontal (12kg.)

g is the ACCELERATION due to gravity

t=¶Mg......EQ{1)

where t is the tension in the string.

for second block of mass m

t=mg.......EQ(2)

equate these two equation because tension in the string is same at all points.

¶Mg=mg

put values.

¶(12)=8

¶=0.66

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