Question

Please solve it !!!!!!

Maths !

Answer 1

Answer:

Step-by-step explanation:

V=1/3x AxH

A=area of base

H=height

H^2=5^2-2$\sqrt{2}$^2

H^2=25-8

H^2=17

H=$\sqrt{17}$

Volume of Pyramis=(1/3)x AxH

Area of base=$\sqrt{3$/4(side x side)

Volume=1/3 x $\sqrt{3$/4 x (4 x 4) x $\sqrt{17}$

=4$\sqrt{51}$/3

Answer 2

Answer:

V=1/3x AxH

A=area of base

H=height

H^2=5^2-2\sqrt{2}2 ^2

H^2=25-8

H^2=17

H=\sqrt{17}17

Volume of Pyramis=(1/3)x AxH

Area of base=\sqrt{3 /4(side x side)

Volume=1/3 x \sqrt{3 /4 x (4 x 4) x \sqrt{17}

=4\sqrt{51}51 /3