Question

please solve it my friends

Answer 1

Answer:

$\frac{2+3i}{4+2i}=\frac{14+8i}{20}$

Step-by-step explanation:

This is a fraction of complex numbers. Complex numbers are the numbers which includes all the real numbers and the roots of the negative numbers.

A complex number has two parts, one is the real part and the other is imaginary part. Real part is a real number whereas imaginary part is also a areal number together with the term i, which is the root of $-1$.

The general form of a complex number is $a+ib$,

where $a$ is the real part and $ib$ is the imaginary part.

When we get a complex fraction, multiply it with the conjugate of the denominator.

conjugate of $a+ib$ is $a-ib$.

Therefore here

$\frac{2+3i}{4+2i}*\frac{4-2i}{4-2i}\\\\ =\frac{(2+3i)(4-2i)}{(4+2i)(4-2i)}$

$=\frac{8-4i+12i+6}{16+4}\\\\=\frac{14+8i}{20}$.

Hence the answer

thank you

Answer 2

Answer:

Step-by-step explanation: