Question

please solve it .
my humble request to you

Answer 1

$\textbf { !! Hey Mate !! }$

your answer is ---

Given, a = $\frac{2 + \sqrt{3} }{2 - \sqrt{3} }$
and, b = $\frac{2 - \sqrt{3} }{2 + \sqrt{3} }$

now,
$a + b = \frac{2 + \sqrt{3} }{2 - \sqrt{3} } + \frac{2 - \sqrt{3} }{2 + \sqrt{3} } \\ \\ = > a + b = \frac{ {(2 + \sqrt{3)} }^{2} + {(2 - \sqrt{3)} }^{2} }{ {2}^{2} - { \sqrt{3} }^{2} } \\ \\ = > a + b = \frac{2 + 3 + 4 \sqrt{3} + 2 + 3 - 4 \sqrt{3} }{4 - 3} \\ = > a + b = \frac{10}{1} \\ = > a + b = 10$

$\textbf { !! Hope it help you !! }$

Answer 2

hope it helps you buddy