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We are given that,
- Sec A + Tan A = p
We are required to find the value of:
- Sec A - Tan A
We know that,
→ Sec²A - Tan²A = 1
Expanding the above identity we get,
→ ( Sec A + Tan A ) ( Sec A - Tan A ) = 1
Substituting ( Sec A + Tan A ) as p, we get:
→ p ( Sec A - Tan A ) = 1
→ Sec A - Tan A = 1/p
Therefore the value of ( Sec A - Tan A ) = 1/p
Some important Trigonometric Identities:
- Sin²A + Cos²A = 1
- Sec²A - Tan²A = 1
- Cosec²A - Cot²A = 1
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