Question

Please solve it. Number 5. Very urgent please. Solve it quickly​

Answer 1

Answer:

log (4y - 3) = log (2y + 1) - log 3

=> log (4y-3) - log (2y+1) + log 3 = 0

=> log [ (4y-3)(3)/(2y+1) ] = 0 [ log m - log n = log (m/n), log m + log n = log (m×n) ]

=> log [ (12y - 9)/(2y + 1) ] = log 1

=> taking antilog on both sides,

(12y - 9)/(2y + 1) = 1

=> 12y - 9 = 2y + 1

=> 12y - 2y = 1 + 9

=> 10 y = 10

=> y = 1