Question

please solve it on a paper ( *do not type on the answer box ,attach a pic of the paper in which sol. is solved)
with a detail explanation​​

Answer 1

Answer:

x = 5/6.

Step-by-step explanation:

    $\sqrt{32^{0}+\frac{2}{3} } = (0.6)^{2-3x}$

=> $\sqrt{(1) +\frac{2}{3} } = (0.6)^{2-3x}$

=> $\sqrt{\frac{5}{3} }= (0.6)^{2-3x}$

=> $\sqrt{\frac{5}{3} } = (\frac{3}{5})^{2} (\frac{5}{3} )^{3x}$

=> $(\frac{5}{3})^{\frac{1}{2}} *(\frac{5}{3})^{2}= (\frac{5}{3})^{3x}$

=> $(\frac{5}{3} )^{2+\frac{1}{2} }= (\frac{5}{3}) ^{3x}$

=> 3x = 2 +1/2

=> 3x = 5/2

=> x = 5/6

Answer 2

Answer:

answer for the given problem is given