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Step-by-step explanation:
(3,4,5)
let the smallest even no. be 2m.
2m = 4
m=2
Now, find (2m, m square -1, m square +1)
so, (2×2, 4-1, 4+1)
( 4, 3, 5)
therefore, It is a Pythagorean triplet.
(6,7,8)
let the smallest even no be 2 m.
2m=6
m=3
Now, find (2m, m square-1, m square+1)
so,. (2×3, 9-1, 9+1)
(6, 8, 10)
therefore,It is not a Pythagorean triplet
(10,24,26)
let the smallest even no be 2.
2m=10
m=5
Now, find (2m, m square -1, m square+1)
(2×5, 25-1, 25+1)
(10, 24, 26)
therefore, it is Pythagorean triplet.
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khushi5342:
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