Question

please solve it please help​

Answer 1

Explanation:

MULTIPLE EQUATION 1 WITH. 3..BOTH SIDE..

$500 \times 3 = px \frac{2}{5} \times 3 + py \frac{3}{5} \times 3$

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$1500 = \frac{6}{5} px + \frac{9}{5} py$

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MULTIPLE EQUATION second with 2 both the side...

$400 \times 2 = px \frac{3}{5} \times 2 + py \frac{2}{5} \times 2$

$800 = \frac{6}{5} px + \frac{4}{5} py$

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now substrate eq 1 with eq 2

we get

$\frac{6}{5} px + \frac{9}{5} py - \frac{6}{5} px - \frac{4}{5} py = 1500 - 800$

$\frac{9 - 4}{5} py = 700$

$py = 700$

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NOW PUT THE VALUE OF PY IN EQ 1

$1500 = \frac{6}{5} px + \frac{9}{5} \times 700$

$1500 = \frac{6}{5} px + 1260$

$px = 200.$

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Answer 2

Your answer is

P°x = 200

P°y = 700

Explanation

Given ,

$500 = px \frac{2}{5} + py \frac{3}{5} \\ 400 = px \frac{3}{5 } + py \frac{2}{5}$

P°x = Px

( Say )

P°y = Py

$500 = \frac{px2 + py3}{5} \\ 2500 = px2 + py3 \\and \\ 400 = \frac{px3 + py2}{5} \\ 2000 = px3 + py2$

• Px = X

( Say )

• Py = Y

So ,

2x + 3y = 2500.........« 1 »

3x + 2y = 2000..........« 2 »

Subtracting (1) - (2) , we get ,

• y - x = 500

• y = ( 500 + x )

Putting the value of y in ( 1 ) ,

• 2x + 3 ( 500 + x ) = 2500

• 2x + 1500 + 3x = 2500

• 5x = 1000

• x = 200

So ,

• y = 500 + x = 500 + 200 = 700

Hence ,

• P°x = Px = x = 200

• P°y = py = y = 700

$\rule{200}{4}$

Checking answer ,

• P°x * 2 / 5 + P°y *3 / 5

if P°x = 200 and P°y = 700 ,

• 200 x 2 / 5 + 700 x 3 / 5

• = 500

Similarly ,

• With equation ( ii )

• 200 x 3 / 5 + 700 x 2 / 5

• = 400