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Find Angle AOB
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Answered by
2
Answer:
<AOB+<BOC=180°(linear pair)
=x+25+3x+15=180
=4x+40=180
=4x=180-40
4x=140
x=140/4
x=35°
So,the <AOB=x+25
put the value of x
then,
35+25=60
<AOB=60°
Answered by
1
Answer:
x + 25 + 3x + 15 = 180 (straight line property)
4x + 40° = 180°
4x = 140°
x = 140°/4 = 35° 1)Ans...
Now,
angleAOB = x + 25°
= 35° + 25°
= 60° 2)Ans...
And angleBOC = 3x + 15 °
=3 × 35° + 15°
= 105° + 15°
= 120° 3)Ans...
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