Question

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please solve class 12 chapter electric potential and capacitance​

Answer 1

Answer:

The given situation is equivalent to three capacitors C1,C2 and C3 in series,

C1=ε0K1Ad1,C2=ε0K2Ad2,C3=ε0K3Ad3

Equivalent.capacitance (C) is given by

1C=1C1+1C2+1C3=1ε0(d1K1+d2K2+d3K3)

Here, A=2m2,K1=2,K2=3;K3=6

d1=0⋅4mm=4×10−4m

d2=0⋅6mm=6×10−4m

d3=1⋅2mm=12×10−4m

ε0=8⋅85×10−12C2N−1m−2

Also, d1K1=d2K2=d3K3=2×10−4m

∴1C=3ε0Ad1K1;C=ε0AK13d1

=8.85×10−12×23×2×10−4=2.95×10−8F

Explanation:

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