Question

please solve it plzzzzzzzzz this very important​

Answer 1

Step-by-step explanation:

12) given points A(1,2m) and B ( -1+2m,2l-2m)

mid point of AB is (1-1+2m/2,2m+2l-2m/2)

=(2m/2,2l/2)

=(m,l)

13)given points A(0,0);B(4,-3);C(x,y) are collinear

so the area of ABC =0

1/2[(0+(4y+3x)+0)]=0

4y+3x=0(eq 1)

and also distance AB=AC

AB2=AC 2

(4-0)*2+(-3-0)*2=(x-0)*2+(y-0)*2

16+9= x2+y2

x2+y2=25

from 1

y=-3x/4

x*2+(-3x/4)*2=25

x*2+9x*2/16=25

25x*2= 16×25

X2=16

x= 4

y=-3(4)/4=-3

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