please solve it properly ,according to class 7 , full explanation
1 . PQR is a triangle , right angled at P. If PQ = 10 cm and PR= 24 cm , find QR
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Step-by-step explanation:
Given: PQ = 10 cm, PR = 24 cm
Let QR be x cm.
In right angled triangle QPR,
(Hypotenuse)2= (Base)2+ (Perpendicular)2 [By Pythagoras theorem]
⇒ (QR)2= (PQ)2+ (PR)2
⇒ x2=(10)2+(24)2
⇒ x2 = 100 + 576 = 676
⇒ x=
√
676
= 26 cm
Thus, the length of QR is 26 cm.
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