Question

Please Solve it Properly :----



$\frac{17(2 - x) \: - 5(x + 12) }{1 - 7x} \: = \: 8$
​

Answer 1

Step-by-step explanation:

Please Solve it Properly :----Please Solve it Properly :----Please Solve it Properly :----

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question:- }}}$

$\bf\frac{17(2 - x) \: - 5(x + 12) }{1 - 7x} \: = \: 8$

$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\:\frac{17(2 - x) \: - 5(x + 12) }{1 - 7x} \: = \: 8 }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{\frac{34 - 17x \: - 5x - 60}{1 - 7x} \: = \: \frac{8}{1} }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{\frac{ - 22x \: - 26}{1 \: - \: 7x} \: = \: \frac{8}{1} }}$

Using Cross Multiplaction:-

$\qquad \quad {:} \longrightarrow \sf{ \bf{1 \times ( - 22x - 26) \: = \: 8 \times (1 - 7x) }}$

$\qquad \quad {:} \longrightarrow \sf{ \sf{ - 22x - 26 \: = \: 8 - \: 56x }}$

$\qquad \quad {:} \longrightarrow \sf{ \sf{ - 22x \: + \:56x \: = \: 8 + \:26 }}$

$\qquad \quad {:} \longrightarrow \sf{ \sf{ 34x \: = \: 34 }}$

$\qquad \quad {:} \longrightarrow \sf{ \sf{ x \: = \: \frac{34}{34} }}$

$\qquad \quad {:} \longrightarrow \sf{ \bf{ x \: = \: \cancel \purple{\frac{34}{34}} }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ \:x \: = \: 1 }}}$

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More For Knowledge :-

$\underbrace\red{\boxed{ \sf \green{ Rules \: to \:Solve \: a \: Equation}}}$

• Rule 1 :- Same quantity ( number ) can be added to both side of an equation without changing the equality.
• Rule 2 :- Same quantity can be subtracted from both sides of an equation without changing the quality
• Rule 3 :- Both sides of an equation may be multiplied by the same non zero number without changing the quality.
• Rule 4 :- Both sides of an equation may be divided by the same non zero number without changing the quality.

$\begin{gathered}\\ \\\end{gathered}$

Note :-

• It should be noted that some complicated equation can be solved by using two or more of these rules together.

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