Question

please solve it q no 68​

Answer 1

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❄ Given:

$\quad\bullet \bf\bigg( { \frac{x}{x + 1} \bigg) }^{2} - 5 \bigg(\frac{x}{x + 1} \bigg) + 6 = 0 \: \:$

• x is not equals to -1

SOLUTION:

$\\ \qquad \implies \displaystyle \sf \: \bigg( { \frac{x}{x + 1} } \bigg)^{2} - 5 \bigg( \frac{x}{x + 1} \bigg) + 6 = 0$

$\: \: \star \qquad\bold{ \bf{put \: \frac {x}{x + 1} \: as \: a \: t }} \: \: \: \: \: ...eqn(1)$

$\: \\ \qquad \implies \displaystyle \sf \: {t}^{2} - 5t + 6 = 0 \: \: \: \: \: ....quadratic \: equation$

$\: \\ \qquad \implies \displaystyle \sf \: {t}^{2} - 6t + t - 6 = 0$

$\: \: \\ \qquad \implies \displaystyle \sf \: t(t - 6) + 1(t - 6) = 0$

$\: \\ \qquad \implies \sf \: t = 6 \: \: and \: t = - 1$

$\: \\ \implies \displaystyle \bf{ \: put \: the \: value \: in \: equation \: (1)}$

$\: \qquad\implies \displaystyle \bf \: \frac{x}{x + 1} = t$

$\: \qquad \implies \displaystyle \bf \frac{x}{x + 1} = 6$

$\: \: \qquad \implies \displaystyle \bf \: x = 6x + 6$

$\: \qquad\implies \displaystyle \bf \: x - 6x - 6 = 0$

$\: \qquad \implies \displaystyle \bf \: - 5x - 6 =0$

$\: \\ \: \qquad \implies \boxed{\displaystyle{ \bf{ {x = \frac{ - 6}{5} }}}} \: is \: the \: answer$

Answer 2

IT'S ANSWER IS 6278

67/0

46x 67 = 788