Math, asked by anushka15012009, 9 months ago

please solve it q no 68​

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Answered by aryan073
1

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Given:

  \quad\bullet \bf\bigg( { \frac{x}{x + 1} \bigg) }^{2}  - 5  \bigg(\frac{x}{x + 1}  \bigg) + 6 = 0 \:  \:

  • x is not equals to -1

SOLUTION:

 \\  \qquad \implies \displaystyle \sf \:  \bigg( { \frac{x}{x + 1} } \bigg)^{2}  - 5 \bigg( \frac{x}{x + 1}  \bigg) + 6 = 0

 \:   \: \star  \qquad\bold{ \bf{put \:  \frac {x}{x + 1} \: as \: a \: t }} \:  \:  \:  \:  \: ...eqn(1)

 \: \\   \qquad \implies \displaystyle \sf \:  {t}^{2}   - 5t + 6 = 0 \:  \:  \:  \:  \: ....quadratic \: equation

 \:   \\ \qquad \implies \displaystyle \sf \:  {t}^{2}  - 6t + t - 6 = 0

 \: \:  \\  \qquad \implies \displaystyle \sf \: t(t - 6) + 1(t - 6) = 0

 \:  \\  \qquad \implies \sf \: t = 6 \:  \: and \: t =  - 1

 \: \\   \implies \displaystyle \bf{ \: put \: the \: value \: in \: equation \: (1)}

 \:   \qquad\implies \displaystyle \bf \:  \frac{x}{x + 1}  = t

 \:  \qquad \implies \displaystyle \bf \frac{x}{x + 1}  = 6

 \:  \:  \qquad \implies \displaystyle \bf \: x = 6x + 6

 \:   \qquad\implies \displaystyle \bf \: x - 6x - 6 = 0

 \:  \qquad \implies \displaystyle \bf \:  - 5x - 6 =0

 \:  \\  \:  \qquad \implies  \boxed{\displaystyle{ \bf{ {x =  \frac{ - 6}{5} }}}} \: is \: the \: answer

Answered by Anantkumar18
0

IT'S ANSWER IS 6278

67/0

46x 67 = 788

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