Question

please solve it.... ques no.2 and 3
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Answer 1

Step-by-step explanation:

2)s= a+b+c/2

51 +37+20/2

=54

area = √s(s-a)(s-b)(s-c)

= √54 (54-51)(54-37)(54-20)

=√54(3)(17)(34) {simplest form}

= √(3*2*3*3)*(3)*(17)*(17*2)

= 3*2*3*17

= 306m²

area needed for flower beds

= 306/9

= 34

∴ 34 flower beds are required to occupy the space

3)Semi perimeter=(a+b+c)/2

=180/2=90 m.

Area: \sqrt{s(s-a)(s-b)(s-c)}

⇒ \sqrt{90(90-65)(90-65)(90-50)}

⇒ \sqrt{90*25*25*40}

= \sqrt{5 ^{6}*2 ^{4} *3^{2} }

⇒125*4* 3

⇒1500 m2

Cost:1500*7

=Rs.10500

Ans:Rs.10500.

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